$2\left[ \begin{matrix} a \\ -b \\ \end{matrix} \right]+4\left[ \begin{matrix} -b \\ \frac{a}{2} \\ \end{matrix} \right]=\left[ \begin{matrix} 5 \\ 3 \\ \end{matrix} \right]\Rightarrow \left[ \begin{matrix} 2a \\ -2b \\ \end{matrix} \right]+\left[ \begin{matrix} -4b \\ 2a \\ \end{matrix} \right]=\left[ \begin{matrix} 5 \\ 3 \\ \end{matrix} \right]$
$\begin{align} & _{-}\left\{ \begin{matrix} 2a-4b=5 \\ 2a-2b=3 \\ \end{matrix} \right.\Rightarrow \left\{ \begin{matrix} \not{2a}-4b=5 \\ \underline{\not{-2a}+2b=-3} \\ \end{matrix} \right. \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-2b=2\Rightarrow b=-1,a=\frac{{}}{2} \\ \end{align}$ $\Rightarrow a+b=\frac{+1}{2}-1=\frac{-1}{2}$