اگر اندازهٔ اضلاع را 3 و 5 و 11 در نظر بگیریم.

$\left. {\begin{array}{*{20}{c}}
  {a = 11} \\ 
  {b = 5} \\ 
  {c = 3} 
\end{array}} \right\} \Rightarrow 2ab + 2ac = 2 \times \left( {11 \times 5} \right) + 2 \times \left( {11 \times 3} \right) = 110 + 66 = 176$

$\left. {\begin{array}{*{20}{c}}
  {a = 3} \\ 
  {b = 11} \\ 
  {c = 5} 
\end{array}} \right\} \Rightarrow 2ab + 2ac = 2 \times \left( {3 \times 11} \right) + 2 \times \left( {3 \times 5} \right) = 66 + 30 = 96$

$\left. {\begin{array}{*{20}{c}}
  {a = 5} \\ 
  {b = 11} \\ 
  {c = 3} 
\end{array}} \right\} \Rightarrow 2ab + 2ac = 2 \times \left( {5 \times 11} \right) + 2 \times \left( {5 \times 3} \right) = 110 + 30 = 140$