اگر $f\left( x \right)=2x+\sqrt{2x}$ باشد، ضابطه تابع حاصل ${{f}^{-1}}\left( x \right)$ کدام است؟
1 )
$\frac{1}{4}\left( 2x-\sqrt{4x+1}-1 \right)\,\,\,\,\,\,\,\,\,\,\,;\,\,\,\,\,\,\,x\ge -\frac{1}{4}$
2 )
$\frac{1}{2}\left( 2x-\sqrt{4x+1}-1 \right)\,\,\,\,\,\,\,\,\,\,\,;\,\,\,\,\,\,\,x\ge -\frac{1}{4}$
$\frac{1}{4}\left( 2x-\sqrt{4x+1}+1 \right)\,\,\,\,\,\,\,\,\,\,\,;\,\,\,\,\,\,\,x\ge 0$
4 )
$\frac{1}{2}\left( 2x-\sqrt{4x+1}+1 \right)\,\,\,\,\,\,\,\,\,\,\,;\,\,\,\,\,\,\,x\ge 0$