طبق رابطهٔ قانون اهم داریم:

$\begin{align}  & R=\frac{V}{I} \\  & \Rightarrow \frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{V}_{1}}}{{{V}_{2}}}\times \frac{{{I}_{2}}}{{{I}_{1}}}\xrightarrow[{{V}_{2}}=1V,{{I}_{2}}=6A]{{{V}_{1}}=0/8V,{{I}_{1}}=8A}\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{0/8}{1}\times \frac{6}{8}=0/6 \\  & \frac{{{R}_{1}}}{{{R}_{3}}}=\frac{{{V}_{1}}}{{{V}_{3}}}\times \frac{{{I}_{3}}}{{{I}_{1}}}\xrightarrow[{{V}_{3}}=1V,{{I}_{3}}=2A]{{{V}_{1}}=0/8V,{{I}_{1}}=8A}\frac{{{R}_{1}}}{{{R}_{3}}}=\frac{0/8}{1}\times \frac{2}{8}=0/2 \\  & \frac{{{R}_{3}}}{{{R}_{2}}}=\frac{{{V}_{3}}}{{{V}_{2}}}\times \frac{{{I}_{2}}}{{{I}_{3}}}\xrightarrow[{{V}_{2}}=1V,{{I}_{2}}=6A]{{{V}_{3}}=1V,{{I}_{3}}=2A}\frac{{{R}_{3}}}{{{R}_{2}}}=\frac{1}{1}\times \frac{6}{2}=3 \\ \end{align}$